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Topic 6: Algebra 2

In this topic, you will understand and use the expansion of algebraic expressions to form and solve quadratic equations.

By the end of this topic, you will be able to:

(a) recognise equivalent quadratic expressions.

(b) expand algebraic expressions.

(c) identify perfect squares.

(d) factorise quadratic expressions.

(e) solve quadratic equations where the quadratic expression can be factorised.

Keywords

  • algebraic expressions
  • expand
  • factories
  • perfect squares
  • quadratic expressions

Introduction

Algebra is widely used in the business sector, especially in the process of determining the selling price of some goods and services before entering the open market.

Wholesalers and retailers may also need to work out the lowest price possible to enable them to realise some minimum profits on certain goods by considering all expenses involved which may include transport, taxes, rent etc. In this topic, you will understand and use the expansion of algebraic expressions to form and solve quadratic equations.

6.1 Recognising equivalent quadratic expression

Activity 6.1 Recognising equivalent quadratic expressions

1. What is the area of each of the following rectangles?

(a)

2. What can you comment about your answers in (1)?

3. Share your ideas with your classmates.

Learning point

You should recognise and interpret equivalent quadratic equations.

Exercise 6.1

Comment TRUE or FALSE for each of the following.

(a) a(a + 4) = a2 + 4a

(b) a(a – 4) = a2 + 4a

(c) 3a(a + b) = 3a2 + 3ab

(d) a(a + 3) = 2a + 3

6.2 Expanding algebraic expressions

Activity 6.2 Expanding algebraic expressions

A father has separated his garden among 4 of his children Mathew, Mark, Mary and Mercy. The small garden was separated like this.

Algebra

1. Find the area for each of the children.

2. What is the total area of their father’s garden?

3. How else can you get that total you got in (2) above?

4. Share your work with the class. Learning point You have learnt to expand algebric equations.

Exercise 6.2

  1. Obtain the areas of rectangles with the following dimensions.
    • (a) (t+4) cm by (t + 3) cm
    • (b) (t+5) cm by (t-3) cm
    • (c) (t-1) cm by (t – 6) cm
  2. In a shop, some pens cost sh (t + 3) and the rest cost sh (t+5). The pens which cost sh(t + 3) are (t – 4) while the rest of the pens which cost sh (t + 5) are (t + 8). Find the total cost of all the pens in the shop in terms of t.
  3. A rectangular garden has sides (x+9) metres by (x-3) metres. Find the area of the rectangle in terms of x.

6.3 Identifying perfect squares

Activity 6.3 Identifying perfect squares

1. Find the area of a square with side a + b.

2. Find the area of a square with side a + 1.

3. Find the area of a square with side a +2.

4. What do you realise from the areas in (1), (2) and (3)? Learning point The identity (a + b)2=a2+2ab+b2

Exercise 6.3

1. Complete the missing information in each of the following.

(a) (t+4)2= (t)2 + (2)(t) (4) …….+……………..

(b) (t-4)2 = 2……..- (2)(t) (4) +…….. =……………..

2. Write the missing information in the boxes and then write down the final square expressions.

(a) (2t+5)2 (b) (2t-5)2

3. Identify perfect squares from the following expressions

(a) x2-3x+2.

(b) x2+10x + 25

(c) x2+2x+1

(d) x2-6x+9

(e) 12+18t+81 4.

4. (a) Expand the following.

(i) (t+5)(t+5)

(ii) (t + 1) (t+2)

(b) Are these perfect squares? Explain your answer.

Difference of two squares

Activity 6.4 Using the difference of two squares

In the diagram, the shaded square of length b m is inscribed in a square of length a m.

  1. What is the area of the square whose length is a m?
  2. What is the area of the shaded square?
  3. How would you obtain the area of the unshaded part in terms of a and b
  4. Draw a sketch of the unshaded part.
  5. How would you find the area of part drawn in (4)?
  6. Relate the area you obtained in (3) to the area in (5)

Learning point

The identity a2 – b2 = (a + b)(a – b)

Exercise 6.4

Factorise the following expressions.

(a) x2-y2 (b) y2-49

(b) z2-81 (d) x2-16y2

(c) 9×2-y2 (1) 81y2-25

(d) 16a2b2-4×2

(h) 4a2z4-36

6.4 Factorising quadratic expressions

This will be a back process of expansion of algebraic expression you did in section 6.2. In this section, you will deal with quadratic expressions of the form: x2 + bx + c.

Activity 6.5 Factorising quadratic expressions

The area of a rectangle is given by x2 + 3x + 2. The different sections of the rectangle have areas as follows.

Find the size of the sides of the rectangle. Relate the sides of the rectangle in (1) with the area of the rectangle. 3. Share your work with the class. Example Consider a rectangle whose dimensions are (t + a) and (t + b).

From the rectangle,

Area =t2+(axt) + (b xt) + (axb)

=12+(a + b)t + ab

Total area = t2+ (sum)t + (product)

The process of factorisation involves working backwards to obtain factors

i.e, t2 + (a + b)t + ab = t2+ at + bt + ab

=t(t + a) + b(t + a)

= (t + a)(t + b)

Exercise 6.5

1. Factorise the following.

(a) t2 + 7t+6

(b) t2 8t+16

(c) t2 + 11t12

(d) t2 – 6t-7

2. Factorise:

(a) t(t+5)+8(t +5)

(b) t2 + 14t+49

(c) t2-16t+64

3. The area of a square is (t2 + 8t+16) cm2. Find the length and the width of the square in centimetres.

6.5 Solving quadratic equations by factorisation

Example

Solve the equation: x2 + 5x + 6 = 0

Solution

Referring to section 6.4, this requires that you find two factors of 6 that add up to 5. These are: 2 and 3. Thus, you will have:

x + 5x + 6 = 0

x2+(2+3)x+6=0

x2 + 2x + 3x+6=0

x(x+2)+3(x+2)=0

(x+2)(x+3)=0

This means that:

Either (x+2) = 0 or (x+3)= 0

Therefore x = -2, x = -3

Exercise 6.6

Solve the following.

(a) t2+7t+6=0

(b) t2+11t-12=0

(c) t28t+16=0

(d) t2-6t-7=0

Assignment

Topic 6: Algebra 2 – Sample Activity

ASSIGNMENT : Topic 6: Algebra 2 – Sample Activity MARKS : 10  DURATION : 1 week, 3 days

 

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